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Oracle遞歸查詢簡單示例
瀏覽:189日期:2023-03-12 15:25:41
目錄
- 1 數據準備
- 2 start with connect by prior遞歸查詢
- 2.1 查詢所有子節點
- 2.2 查詢所有父節點
- 2.3 查詢指定節點的,根節點
- 2.4 查詢巴中市下行政組織遞歸路徑
- 3 with遞歸查詢
- 3.1 with遞歸子類
- 3.2 遞歸父類
- 補充:實例
- 總結
1 數據準備
create table area_test( id number(10) not null, parent_id number(10), name varchar2(255) not null);alter table area_test add (constraint district_pk primary key (id));insert into area_test (ID, PARENT_ID, NAME) values (1, null, "中國");insert into area_test (ID, PARENT_ID, NAME) values (11, 1, "河南省"); insert into area_test (ID, PARENT_ID, NAME) values (12, 1, "北京市");insert into area_test (ID, PARENT_ID, NAME) values (111, 11, "鄭州市");insert into area_test (ID, PARENT_ID, NAME) values (112, 11, "平頂山市");insert into area_test (ID, PARENT_ID, NAME) values (113, 11, "洛陽市");insert into area_test (ID, PARENT_ID, NAME) values (114, 11, "新鄉市");insert into area_test (ID, PARENT_ID, NAME) values (115, 11, "南陽市");insert into area_test (ID, PARENT_ID, NAME) values (121, 12, "朝陽區");insert into area_test (ID, PARENT_ID, NAME) values (122, 12, "昌平區");insert into area_test (ID, PARENT_ID, NAME) values (1111, 111, "二七區");insert into area_test (ID, PARENT_ID, NAME) values (1112, 111, "中原區");insert into area_test (ID, PARENT_ID, NAME) values (1113, 111, "新鄭市");insert into area_test (ID, PARENT_ID, NAME) values (1114, 111, "經開區");insert into area_test (ID, PARENT_ID, NAME) values (1115, 111, "金水區");insert into area_test (ID, PARENT_ID, NAME) values (1121, 112, "湛河區");insert into area_test (ID, PARENT_ID, NAME) values (1122, 112, "舞鋼市");insert into area_test (ID, PARENT_ID, NAME) values (1123, 112, "寶豐市");insert into area_test (ID, PARENT_ID, NAME) values (11221, 1122, "尚店鎮");
2 start with connect by prior遞歸查詢
2.1 查詢所有子節點
select *from area_teststart with name ="鄭州市"connect by prior id=parent_id
2.2 查詢所有父節點
select t.*,levelfrom area_test tstart with name ="鄭州市"connect by prior t.parent_id=t.idorder by level asc;
start with 子句:遍歷起始條件,如果要查父結點,這里可以用子結點的列,反之亦然。
connect by 子句:連接條件。prior 跟父節點列parentid放在一起,就是往父結點方向遍歷;prior 跟子結點列subid放在一起,則往葉子結點方向遍歷。parent_id、id兩列誰放在“=”前都無所謂,關鍵是prior跟誰在一起。
order by 子句:排序。
2.3 查詢指定節點的,根節點
select d.*, connect_by_root(d.id) rootid, connect_by_root(d.name) rootnamefrom area_test dwhere name="二七區"start with d.parent_id IS NULLconnect by prior d.id=d.parent_id
2.4 查詢巴中市下行政組織遞歸路徑
select id, parent_id, name, sys_connect_by_path(name, "->") namepath, levelfrom area_teststart with name = "平頂山市"connect by prior id = parent_id
3 with遞歸查詢
3.1 with遞歸子類
with tmp(id, parent_id, name) as ( select id, parent_id, name from area_test where name = "平頂山市" union all select d.id, d.parent_id, d.name from tmp, area_test d where tmp.id = d.parent_id )select * from tmp;
3.2 遞歸父類
with tmp(id, parent_id, name) as ( select id, parent_id, name from area_test where name = "二七區" union all select d.id, d.parent_id, d.name from tmp, area_test d where tmp.parent_id = d.id )select * from tmp;
補充:實例
我們稱表中的數據存在父子關系,通過列與列來關聯的,這樣的數據結構為樹結構。
現在有一個menu表,字段有id,pid,title三個。
查詢菜單id為10的所有子菜單。
SELECT * FROM tb_menu m START WITH m.id=10 CONNECT BY m.pid=PRIOR m.id;
將PRIOR關鍵字放在m.id前面,意思就是查詢pid是當前記錄id的記錄,如此順延找到所有子節點。
查詢菜單id為40的所有父菜單。
SELECT * FROM tb_menu m START WITH m.id=40 CONNECT BY PRIOR m.pid= m.id ORDER BY ID;
總結
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