Java-使用Runtime.getRuntime（）。exec（無法啟動臨時文件啟動的進程

通過傳遞一組環境變量來解決。

啟動的進程Runtime.getRuntime().exec(cmdLine,envp,workingDirectory);無法創建臨時文件。

在Eclipse的Maven插件中使用

從mvn啟動報價：

Caused by: java.io.IOException: ??????? at java.io.WinNTFileSystem.createFileExclusively(Native Method) at java.io.File.createTempFile(File.java:1879)

完整日志

演示代碼段遇到相同的錯誤。

String mavenPath = 'D:Progsspringsourceapache-maven-3.0.4binmvn.bat';String mavenOptions = '-X compile exec:java -Dexec.mainClass=runclass.Runme';String[] cmdLine = new String[2];cmdLine[0] = mavenPath; //cmdLine.add(mavenPath);cmdLine[1] = mavenOptions; //cmdLine.add(mavenOptions+' compile exec:java -Dexec.mainClass='+packageClass);String[] envp = new String[2];//Map<String,String> envm = new HashMap<String,String>();envp[0] = 'JAVA_HOME=' + System.getProperty('java.home'); //System.getenv('JAVA_HOME');envp[1] = 'M2_HOME=' + System.getenv('MAVEN_HOME');File workingDirectory = null;String currentDir = new File('.').getAbsolutePath();log(currentDir);String userDir = System.getProperty('user.dir'); //User working directory ; 'user.home' User home directoryworkingDirectory = new File(userDir); log(workingDirectory.toString());//Runtime rt = Runtime.getRuntime();Process proc = rt.exec(cmdLine,workingDirectory);InputStream stdout = proc.getInputStream();InputStream stderr = proc.getErrorStream();InputStreamReader isr = new InputStreamReader(stdout);InputStreamReader isr2 = new InputStreamReader(stderr);BufferedReader br = new BufferedReader(isr);BufferedReader br2 = new BufferedReader(isr2);

更新：

傳遞TMP和TEMP環境變量無濟于事。通過 null而不是envp也無濟于事。

如果envp為null，則子進程繼承當前進程的環境設置。